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View Full Version : how many of you have your rwtq and rwhp cross at 5200rpm?



LANDY
07-13-2010, 04:38 PM
As the tittle says. Please post your dyno sheets if possible. :beer:

ntd
07-13-2010, 04:58 PM
mine does
http://www.mercurymarauder.net/gallery/data/500/medium/IMG_12442.JPG

LANDY
07-13-2010, 06:19 PM
Nice. Can anyone explain why that's preferable.?

TooManyFords
07-13-2010, 06:21 PM
Technically, they *all* should.

http://www.mercurymarauder.net/forums/showpost.php?p=897220

FordNut
07-13-2010, 06:22 PM
They all do.

The reason some dyno sheets look like they don't is that the scales for hp and tq are not set to be equal. Look at the numbers on the left and right sides of the graph, if they are the same the traces will always cross at 5200.

TooManyFords
07-13-2010, 06:23 PM
Technically, they *all* should.

http://www.mercurymarauder.net/forums/showthread.php?t=62041

justbob
07-13-2010, 06:23 PM
http://i300.photobucket.com/albums/nn19/marauding4life/rgwegr001.jpg

LANDY
07-13-2010, 07:22 PM
Very interesting. Thanks guys.

martyo
07-14-2010, 03:48 AM
My Marauder has not been on the dyno is years so I don't know where the lines cross.

But....

My car crosses the line at 9.67. Do all Marauders do that?

Bluerauder
07-14-2010, 04:14 AM
Actually, they should all cross at 5,252 RPM. Its a math thing.

LANDY
07-14-2010, 04:16 AM
My Marauder has not been on the dyno is years so I don't know where the lines cross.

But....

My car crosses the line at 9.67 @ 140mph. Do all Marauders do that?
fixed it for ya.

Rockettman
07-14-2010, 04:31 AM
My Marauder has not been on the dyno is years so I don't know where the lines cross.

But....

My car crosses the line at 9.67. Do all Marauders do that?

:rofl: ^^^^^

Joe Walsh
07-14-2010, 04:51 AM
Actually, they should all cross at 5,252 RPM.

Yep, By definition the horsepower should always equal the torque at 5252 rpm:

For a given torque and speed, the power may be calculated.
The standard equation relating torque in foot-pounds, rotational speed in RPM and horsepower is:


HP = (TRQ x rpm) / 5252


The constant 5252 comes from (33,000 ft·lbf/min)/(2π rad./rev.).

martyo
07-14-2010, 05:57 AM
fixed it for ya.

10 q!

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